scala.slick.security.scala-slick-overridesql-literal.scala-slick-overrideSql-literal

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Detected a formatted string in a SQL statement. This could lead to SQL injection if variables in the SQL statement are not properly sanitized. Avoid using non literal values in overrideSql(...).

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Defintion

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rules:
  - id: scala-slick-overrideSql-literal
    patterns:
      - pattern: $MODEL.overrideSql($QUERY,...)
      - pattern-not: $MODEL.overrideSql("...",...)
      - pattern-not-inside: |
          $QUERY = "..."
          ...
    message: Detected a formatted string in a SQL statement. This could lead to SQL
      injection if variables in the SQL statement are not properly sanitized.
      Avoid using non literal values in `overrideSql(...)`.
    languages:
      - scala
    severity: ERROR
    metadata:
      category: security
      cwe:
        - "CWE-89: Improper Neutralization of Special Elements used in an SQL
          Command ('SQL Injection')"
      owasp:
        - A01:2017 - Injection
        - A03:2021 - Injection
      technology:
        - scala
        - slick
      confidence: LOW
      references:
        - https://owasp.org/Top10/A03_2021-Injection
      cwe2022-top25: true
      cwe2021-top25: true
      subcategory:
        - audit
      likelihood: LOW
      impact: HIGH
      license: Commons Clause License Condition v1.0[LGPL-2.1-only]

Examples

scala-slick-overrideSql-literal.scala

import slick.jdbc.H2Profile.api._

class FooBar {
  def something(name: String) = {
    val db = Database.forConfig("h2mem1")

    lazy val people = TableQuery[People]

    // ok: scala-slick-overrideSql-literal
    people.map(p => (p.id,p.name,p.age))
      .result
      .overrideSql("SELECT id, name, age FROM Person")
    
    val query = "SELECT id, name, age FROM Person"
    // ok: scala-slick-overrideSql-literal
    people.map(p => (p.id,p.name,p.age))
      .result
      .overrideSql(query)


    // ruleid: scala-slick-overrideSql-literal
    people.map(p => (p.id,p.name,p.age))
      .result
      .overrideSql(s"SELECT id, name, age FROM Person WHERE $name")
  }
}